(x+2)(3x^2-4x+5)=y

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Solution for (x+2)(3x^2-4x+5)=y equation: 


Simplifying
(x + 2)(3x2 + -4x + 5) = y

Reorder the terms:
(2 + x)(3x2 + -4x + 5) = y

Reorder the terms:
(2 + x)(5 + -4x + 3x2) = y

Multiply (2 + x) * (5 + -4x + 3x2)
(2(5 + -4x + 3x2) + x(5 + -4x + 3x2)) = y
((5 * 2 + -4x * 2 + 3x2 * 2) + x(5 + -4x + 3x2)) = y
((10 + -8x + 6x2) + x(5 + -4x + 3x2)) = y
(10 + -8x + 6x2 + (5 * x + -4x * x + 3x2 * x)) = y
(10 + -8x + 6x2 + (5x + -4x2 + 3x3)) = y

Reorder the terms:
(10 + -8x + 5x + 6x2 + -4x2 + 3x3) = y

Combine like terms: -8x + 5x = -3x
(10 + -3x + 6x2 + -4x2 + 3x3) = y

Combine like terms: 6x2 + -4x2 = 2x2
(10 + -3x + 2x2 + 3x3) = y

Solving
10 + -3x + 2x2 + 3x3 = y

Solving for variable 'x'.

Combine like terms: y + -1y = 0
10 + -3x + 2x2 + 3x3 + -1y = 0

The solution to this equation could not be determined.

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